Q.

The escape velocity from the earth is about 11 km/second. The escape velocity from a planet having twice the radius and the same mean density as the earth, is

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a

22 km/sec

b

11 km/sec

c

5.5 km/sec

d

15.5 km/sec

answer is A.

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Detailed Solution

ve=2GMR=R83πGρ∴ve∝R if ρ= constant Since the planet having double radius in comparison to earth, therefore, the escape velocity becomes twice i.e. 22 km/s.
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