First slide

Gravitaional potential energy

Question

Escape velocity of a projectile from the surface of earth is about :

Easy

A

3 x 10¹⁰ cm/s
B

18600 m/s
C

11.2 km/s
D

8 km/s

Solution

$V_{e s c a p e} = \sqrt{\frac{2 G M}{R}} = \sqrt{2 g R} = \sqrt{2 \times 9.81 \times 6400 \times 10^{3}} \times 10^{- 3} = 11.2 {kms}^{- 1}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App