Questions
The escape velocity on the surface of the earth is 11.2 km/s. If mass and radius of a planet is 4 and 2 times respectively than that of earth, what is the escape velocity from the planet ?
a
11.2 km/sec
b
1.112 km/sec
c
15.8 km/sec
d
22.4 km/sec
detailed solution
Correct option is C
Escape velocity =(2g/R)=2(GM/R)=2×G×4M2R=22GMR=2×11⋅2=15⋅8km/secTalk to our academic expert!
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