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Q.

Escape velocity on the surface of a planet of radius R and density ρ is V. What will be the escape velocity on the surface of a planet of radius 2R and density 4ρ ?

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a

V

b

V2

c

4V

d

2V

answer is C.

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Detailed Solution

(3)Ve=2GMR  =  2G.  43 πR3ρR  = R83 πG.ρ∴  V'eV=R'R  .  ρ'ρ =  2RR . 4ρρ =4.⇒   V'e=4V.
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