Every series of hydrogen spectrum has an upper and lower limit in wavelength. The spectral series which has'an upper limit of wavelength equal to 18752 A0 is (Rydberg constant R = 1.097 x 107 per metre)

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Balmer series

Lyman series

Paschen series

Pfund series

answer is C.

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Detailed Solution

1λ=R1n22−1n22⇒1n12−1n22=1Rλ=11.097×107×18752×10−10=0.0486=7144. But132−142=7144⇒n1=3 and n2=4 Paschen series

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