Q.
The excess of pressure inside the first soap bubble is three times that inside the second bubble. The ratio of volume of the first to second bubble is
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a
1 :3
b
1:9
c
1:27
d
3:1
answer is C.
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Detailed Solution
p∝(1/r) Here p1/p2=3=r2r1 V1V2=r1r23=r13r13=127 V1:V2=1:27
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