Q.

The excess of pressure inside the first soap bubble is three times that inside the second bubble. The ratio of volume of the first to that of the second bubble is

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a

1 : 3

b

1 : 9

c

1 : 27

d

9 : 1

answer is C.

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Detailed Solution

Pe1Pe2=R2R1=31⇒R2=3R1V2V1=271
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