Q.
Excess pressure of one soap bubble is four times more than the other. Then the ratio of volume of first bubble to another one is
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a
1 : 64
b
1 : 4
c
64 : 1
d
1 : 2
answer is A.
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Detailed Solution
ΔP=4Tr⇒ΔP1ΔP2=4 ∴r2r1=4 and V1V2=r1r23=164
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