The excess pressure in a soap bubble of radius 2 mm is Δp. What will be the radius of a soap bubble whose excess pressure is 2Δp/3?
0.66 mm
3 mm
0.5 m
2.5 mm
Δp∝1r⇒r1r=ΔpΔp1=Δp23Δp=1.5
⇒r1=3 mm