In an experiment four quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows:P = a3b2cd% error in P is
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a
14%
b
10%
c
7%
d
4%
answer is A.
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Detailed Solution
P = a3b2cd⇒ ∆PP×100 = 3(∆aa×100)+2(∆bb×100)+(∆cc×100)+(∆dd×100)= 3×1+2×2+3+4= 3+4+3+4 = 14%