In an experiment, four quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows P=a3b2cd. % error in P is

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14%

10%

answer is C.

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Detailed Solution

As P=a3b2cd% error in P is ΔPP×100=3Δaa+2Δbb+Δcc+Δdd×100 =[3×1%+2×2%+3%+4%]=14%

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