In the experiment of Ohm’s law, a potential difference of 5.0V is applied across the end of a conductor of length 10.0 cm and diameter of 5.00mm. The measured current in the conductor is 200 A. The maximum permissible percentage error in the resistivity of the conductor is :

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

8.4

3.9

3.0

7.5

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Ohm's Law, V=IR⇒V=Iρ4Lπd2⇒ρ=πd2VI4L⇒△ρρ×100=2△dd×100+△VV×100+△II×100+△LL×100⇒△ρρ×100=20.015.00×100+0.15.0×100+1200×100+0.110.0×100⇒△ρρ×100=0.4+2+0.5+1=3.9%

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET