First slide

Errors

Question

In an experiment, the percentage of error occurred in the measurement of physical quantities A, B, C and D are 1%, 2 %, 3% and 4% respectively. Then the maximum percentage of error in the measurement $X$ where $X = \frac{A^{2} B^{1 / 2}}{C^{1 / 3} D^{3}}$ will be

Easy

A

$10 %$
B

$(\frac{3}{13}) %$
C

$16 %$
D

$- 10 %$

Solution

$X = \frac{A^{2} B^{1 / 2}}{C^{1 / 3} D^{3}} Maximum percentage error in X (\frac{dX}{X}) \times 100 = (2 \frac{dA}{A} + \frac{1}{2} \frac{dB}{B} + \frac{1}{3} \frac{dC}{C} + 3 \frac{dD}{D}) \times 100 = 2 \times 1 + \frac{1}{2} \times 2 + \frac{1}{3} \times 3 + 3 \times 4 = 16 %$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App