In an experiment, the perceritage of error occurred in the measurement of physical quantities A, B, C and D are 1 %, 2%, 3% and 4%, respectively. Then, the maximum percentage of error in the  measurement X, where X=A2B1/2CV3D3 will be                                                    [NEET 2019]

Given, X=A2B1/2C1/3D3The percentage error in X is given byΔXX×100=2ΔAA×100+12ΔBB×100+13ΔCC×100 +3ΔDD×100…. (i)  Given, ΔAA×100=1%,ΔBB×100=2%ΔCC×100=3%,ΔDD×100=4%Substituting these values in Eq. (i), we getΔXX×100=2(1%)+12(2%)+13(3%)+3(4%)= 2% + 1 % + 1 % + 12% = 16%Thus, maximum % error in X is 16%.