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Q.

An experiment is performed to determine the I-V (Current & Voltage) characteristics of a Zener diode, which has a protective resistance of R=100Ω , and diode has maximum power of dissipation rating of 1W. The minimum voltage range of the DC source in the circuit is:

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a

0-5 V

b

0-24V

c

0-12V

d

0-8V

answer is B.

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Detailed Solution

∵P=1W,   R=100Ω,P=i2R ⇒1=i2100 ⇒i=0.1AV=iR+VD ⇒VD=V-iR=V-i100Power dissipation diode=P=iVD ⇒1=iV-i100 ⇒100i2-Vi+1=0   For real values of current, V2-41001≥0 ⇒V≥20V
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