In the experiment on photoelectric effect, the graph between EK(max) and v is found to be a straight line as shown in figure. The threshold frequency and Planck's constant according to this graph are
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a
3.33×1018s−1,6×10−34J−s
b
6×1018s−1,6×10−34J−s
c
2.66×1018s−1,4×10−34J−s
d
4×1018s−1,3×10−34J−s
answer is A.
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Detailed Solution
Kmax=hv−Wω is the intercept on y -axis and h is the slope. ∴ h=2.4×10−154×1018=6×10−34JsW=2×10−15J⇒ hv0=2×10−15 or v0=3.33×1018s-1