Experiment shows that two perfectlly neutral parallel metal plates separated by a small distance d, attract each other via a very weak force, known as the Capacitive force. The force per unit area of the plates, F, depends only on the Planck constant h, on the speed of light c, and on d. Which of the following has the best chance of being correct for F?

FA = newtonm2=ML-1T-2Assuming assuming FA=hxCydZ then ML-1T-2=ML2T-1xLT-1yLz M1=Mx   so   x=1 L-1=L2x+y+z ;  y+z=-3 T-2=T-x-y ;   2=x+y  substituting y=1  then z=-4 FA=hcd4alternate method hcd2= joule-s. (metres.)1(metre)2= joulemetre = newtonhcd4 = (hcd2)1d2 = newtonm2. Hence F = hcd4hdc = joule.s(metre)2(metres.)  = newton-metre2s2d4hc = 1(hcd4) = mnewton