In an experiment on the specific heat of a metal, a 0.20 kg block of the metal at 150°C is dropped in a copper calorimeter (of water equivalent 0.025 kg) containing 150 cc of water at 27°C. The final temperature is 40°C. If heat losses to the surroundings is not negligible, then the value of specific heat (in cal/g°C) of the metal will be_____

Here, mass of metal, m = 0.20 kg =200 gFall in temperature of metal           ΔT=150∘C−40∘C=110∘CIfe is specific heat of the metal, then heat lost by the metal,                     ΔQ=mcΔT=200s×110   ……….(i)Volume of water = 150 ccMass of water, m' = 150gWater equivalent of calorimeter                         w=0.025kg=25gRise in temperature of water in calorimeterΔT′=40∘C−27∘C=13∘CHeat gained by water and calorimeter      ΔQ′=m′+wΔT′=(150+25)×13      ΔQ′=175×13    .........(ii)As ΔQ=ΔQ′∴ From Eqs. (i) and (i), we get200×s×110=175×13s=175×13200×110≈0.10 J/g∘C