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Q.

In an experiment with potentiometer to measure the internal resistance of a cell, when the cell is shunted by 5Ω , the null point is obtained at 2m. When cell is shunted by 20Ω the null point is obtained at 3m. The internal resistance of cell is

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a

2Ω

b

4Ω

c

6Ω

d

8Ω

answer is B.

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Detailed Solution

V1V2=I1I2V1=ER1+rR1,V2=ER2+rR2R1R2+rR2R1+r=l1l2⇒r=4Ω
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In an experiment with potentiometer to measure the internal resistance of a cell, when the cell is shunted by 5Ω , the null point is obtained at 2m. When cell is shunted by 20Ω the null point is obtained at 3m. The internal resistance of cell is