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In an experiment with potentiometer to measure the internal resistance of a cell, when the cell is shunted by $5 Ω$ , the null point is obtained at $2 m$ . when cell is shunted by $20 Ω$ the null point is obtained at $3 m$ .The internal resistance of cell is

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detailed solution

Correct option is B

Resistance R1=5 Ω Resistance R2=20 Ω Balancing length l1=2 m Balancing length l2=3 m Internal resistance r=? l1l2=R1R2[R2+rR1+r] 23=520(20+r5+r) ∴ r=4 Ω

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In an experiment with potentiometer to measure the internal resistance of a cell, when the cell is shunted by 5Ω , the null point is obtained at2 m . when cell is shunted by 20Ω the null point is obtained at3 m .The internal resistance of cell is

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Ready to Test Your Skills?

free study material

In an experiment with potentiometer to measure the internal resistance of a cell, when the cell is shunted by $5 Ω$ , the null point is obtained at $2 m$ . when cell is shunted by $20 Ω$ the null point is obtained at $3 m$ .The internal resistance of cell is