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Law of conservation of momentum and it's applications

Question

An explosion blows a rock into three parts. Two pieces go off at right angles to each other; 1.0 kg piece with a velocity of 12 m/s and other 2.0 kg piece with a velocity of 8 m/s. If the third piece flies off with a velocity of 40 m/s, compute the mass of the third piece (in kg).

Moderate
Solution

Let m1, m2 and m3 be the masses of the three pieces. Given m1 =1.0 kg, m2 = 2.0 kg

Let  v1 =12m/s, v2 =8m/ s, v3 =40 m/s. Let v1 and v2 be directed along x- and y-axes, respectively, and v3 be directed as shown.

By the principle of conservation of momentum, initial momentum is zero. Hence,

 along x-axis: 0=m1v1m3v3cosθ

 along y-axis: 0=m2v2m3v3sinθ

m1v1=m3v3cosθ and m2v2=m3v3sinθ

By squaring and adding, we get

 m32=12(12)2+(2)2(8)2(40)2m3=0.5kg



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