The expression for an AM voltage is $$e=51+0.6Cos1000$$$$π$$$$tCos5$$×$$106$$$$π$$t . Frequencies of sideband is

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The expression for an AM voltage is  $$e=51+0.6Cos1000$$$$π$$$$tCos5$$×$$106$$$$π$$t .  Frequencies of sideband is

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Given equation $$e=51+0.6Cos1000$$$$π$$$$tCos5$$×$$106$$$$π$$t ⇒$$e=(5+3Cos1000$$$$π$$$$t)$$.$$Cos5$$×$$106$$$$π$$t  Standard equation of modulating wave  $$E=(Ec+EmCoswmt)Coswct$$    Comparing  we get,   $$Ec=5$$ , Em $$=$$ $$3$$  wm $$=$$ $$1000$$π ⇒$$2$$$$π$$nm $$=$$ $$1000$$π ⇒$$nm=500$$ Hz   Similarly,  wc $$=$$ $$5$$×$$106$$π ⇒$$2$$$$π$$nc $$=$$ $$5$$×$$106$$π ⇒nc $$=$$ $$25$$×$$105$$ Hz  Upper side band  $$=$$ $$fc+fm=nc+nm$$ $$=$$ $$2500000+500$$ $$=2.5005$$×$$106Hz$$ Lower side band $$=$$ fc−$$fm=nc$$−nm $$=2500000-500$$  $$=2.4995$$×$$106Hz$$

The expression for an AM voltage is $e = 5 (1 + 0. 6Cos1 000 π t) Cos5 \times 10^{6} π t$ . Frequencies of sideband is

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The expression for an AM voltage is e=51+0.6Cos1000πtCos5×106πt . Frequencies of sideband is

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The expression for an AM voltage is $e = 5 (1 + 0. 6Cos1 000 π t) Cos5 \times 10^{6} π t$ . Frequencies of sideband is