The extension in a string, obeying Hooke's law, is x . The speed of sound in the stretched string is v . If the extension in the string is increased to 1.5x, the speed of sound will be
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a
1.22 v
b
1.61 v
c
1.50 v
d
0.75 v
answer is A.
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Detailed Solution
Given , e1=x , e2=1.5 x Speed V=Tμ =YAeμl V∝e V1V2=e1e2=x1.5x ⇒V2=1.22 V1