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Q.

The extension of a wire by application of load is 0.2cm. The extension in a wire of same material but of half the length and double the radius of cross section by the same load will be in (cm)

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a

0.025cm

b

0.2cm

c

0.05cm

d

0.1cm

answer is A.

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Detailed Solution

e∝ℓr2 e1e2=ℓ1ℓ2×(r2r1)2 =2×4=8 0.2e2=8         e2=0.28=0.025
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