Questions
The external and internal diameters of a hollow cylinder are measured to be (4.230.01) cm and (3.89 0.01) cm. The thickness of the wall of the cylinder is:
detailed solution
Correct option is C
D=(4.23±0.01)cmd=(3.89±0.01)cmΔt=(D−d)2 =(4.23±0.01)−(3.89±0.01)2 =(4.23−3.89)±(0.01+0.01)2 =(0.34±0.02)2cm =(0.17±0.01)cmSimilar Questions
To estimate 'g' , error in measurement of L is 2% and error in measurement of T is 3%. The error in estimated 'g' will be:
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