First slide

Capacitance

Question

A 10 μF capacitor is charged by.a battery of emf 100 V. The energy drawn from the battery and the energy stored in the capacitor, are respectively :

Easy

A

0.10 J and 0.05 J
B

0.05 J and 0.10 J
C

1.0 mJ and 0.5 mJ
D

0.05 J and 0.05 mJ

Solution

Charge supplied by battery Q = CV = $10 x 10^{- 6} x 100 = 10^{- 3} C$
Energy drawn from battery= QV = $(10^{- 3}) (100) = 0.1 J$
Energy stored in capacitor = $\frac{1}{2} {CV}^{2} = \frac{QV}{2} = 0.0.5 J$

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