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Q.

A 10 μF capacitor is charged by a 10 V ideal cell. Then ‘E’ joule of chemical energy, initially stored in the cell, is converted into other form of energy. The value of E (in joule) is

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a

1 mJ

b

10 mJ

c

100 mJ

d

1 J

answer is A.

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Detailed Solution

U = Energy stored in the capacitor =12cv2=12 x 10 x 10-6 x (10)2 J=0.5 mJSince efficiency of charging is 50% E=2U=2 x 0.5 mJ=1 mJ

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