A 2μF capacitor is charged to a potential difference 30V and the charging battery is disconnected. It is then connected to a series combination of capacitors C1 = 2μF and C2 = 4μF, as shown. Both C1 and C2 are initially uncharged. When the switch S is closed, charge redistributes. Final potential difference across C1 will be :
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a
8 V
b
10 V
c
12 V
d
18 V
answer is C.
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Detailed Solution
Initial charge = 60μCFrom diagram 60-q2=q2+q4⇒q=24 μCVoltage on C1=q2=12V