Questions
A capacitor is charged to a potential of and a capacitor is charged to . The capacitors are then connected in parallel with plates of opposite polarity joined together. What amount of charge will flow through the connecting wire when the plates are so connected?
detailed solution
Correct option is D
Charge on the first capacitor Q1=C1V1=3×10−6×300=900×10−6 C Charge on the second one Q2=C2V2=2×10−6×200=400×10−6 C When plates with opposite polarity are joint, charge will be 900−400=500μCThe capacity will be C=C1+C2=5 μFCommon potential =500μC5=100 V Final charge on first capacitor =300μCCharge flow =900μC−300μC=600μCTalk to our academic expert!
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