A 16 μF capacitor, initially charged to 5 V, is started charging at t = 0 by a source at the rate of 40t μCs−1. How long will it take to raise its potential to 10V?

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1 s

2 s

3 s

none of these

answer is B.

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Detailed Solution

qi=CVi=16×5=80μC, qf=CVf=16×10=160μCGiven dqdt=40t⇒∫qiqf dq=∫0t 40tor qf−qi=40t22or 160−80=20t2 or t=2s

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