Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A 16 μF capacitor, initially charged to 5 V, is started charging at t = 0 by a source at the rate of 40t μCs−1. How long will it take to raise its potential to 10V?

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

1 s

b

2 s

c

3 s

d

none of these

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

qi=CVi=16×5=80μC, qf=CVf=16×10=160μCGiven dqdt=40t⇒∫qiqf dq=∫0t 40tor qf−qi=40t22or 160−80=20t2 or t=2s
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon