First slide

Electrostatic force

Question

$F_{g}$ and $F_{e}$ represents gravitational and electrostatic force respectively between electrons situated at a distance 10 cm. The ratio of $F_{g} / F_{e}$ is of the order of

Easy

A

10⁴²
B

10
C

1
D

10^-43

Solution

Gravitational force between electrons $F_{G} = \frac{G {(m_{e})}^{2}}{r^{2}}$
Electrostatics force between electrons $F_{e} = k . \frac{e^{2}}{r^{2}}$
$\frac{F_{G}}{F_{e}} = \frac{G {(m_{e})}^{2}}{k . e^{2}} = \frac{6 .67 \times 10^{- 11} \times {(9 .1 \times 10^{- 31})}^{2}}{9 \times 10^{9} \times {(1 .6 \times 10^{- 19})}^{2}} = 2 .39 \times 10^{- 43}$

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