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Q.

F→=ai^+3j^+6k^ and r→=2i^−6j^−12k^ The value of ‘a’ for which the angular momentum is conserved is

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a

-1

b

0

c

1

d

2

answer is A.

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Detailed Solution

τ→=r→×F→ and τ=dLdt=0 i.e.   r→ and F→ are parallel a2=3-6=6-12 a=-1
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F→=ai^+3j^+6k^ and r→=2i^−6j^−12k^ The value of ‘a’ for which the angular momentum is conserved is