In the far field diffraction pattern of a single slit under polychromatic illumination, the first minimum with the wavelength λ1 is found to be coincident with the third maximum at λ2 . So
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a
3λ1=0.3λ2
b
3λ1=λ2
c
λ1=3.5λ2
d
0.3λ1=3λ2
answer is C.
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Detailed Solution
Position of first minima = position of third maxima i.e., 1×λ1Dd=(2×3+1)2λ2Dd ⇒λ1=3.5λ2
In the far field diffraction pattern of a single slit under polychromatic illumination, the first minimum with the wavelength λ1 is found to be coincident with the third maximum at λ2 . So