First slide

The optical instruments

Question

The far point of a myopia eye is at 40 cm. For removing this defect, the power of lens required will be

Moderate

A

40 D
B

– 4 D
C

– 2.5 D
D

0.25 D

Solution

For myopic eye f = – (defected far point)
$\Rightarrow f = - 40 cm \Rightarrow P = \frac{100}{- 40} = - 2 .5 D$

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