A fat hose pipe is held horizontally by a fireman. It delivers water through a constricting nozzle at $$1$$ $$litre/$$$$sec$$. If by increasing the pressure, the water is delivered at $$2$$ $$litre/$$$$sec$$, the fireman now has to

Question

Infinity Learn · Accepted Answer

If 'Q' be the discharge through the nozzle , then the force applied by water on the nozzle is given by F $$=$$ $$p(1/a-1/A)$$.$$Q2$$ . Where a $$=$$ nozzle area , A $$=$$ cross sectional area of hose and p $$=$$ density of water . Therefore  F α $$Q2$$ . So when the discharge becomes two times , force on the nozzle becomes four times and this force acts in the forward direction . So the fireman has to push backward $$4$$ times as hard

A fat hose pipe is held horizontally by a fireman. It delivers water through a constricting nozzle at 1 litre/sec. If by increasing the pressure, the water is delivered at 2 litre/sec, the fireman now has to

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