A fax message is to be sent from Delhi to Australia via a geostationary satellite. Calculate the minimum time delay between the dispatch and its getting received is y×10−3 (in sec) , then y is (Height of geostationary satellite = 36,000 km)

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answer is 0240.00.

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Detailed Solution

Minimum distance = S = 2h =2×36000km=72000km =72000×1000m Minimum time delay = t = ? t=SC=720000003×108=24×10−2 sec=240×10−3 s

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