Propagation of electromagnetic waves

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Question

A fax message is to be sent from Delhi to Washington via a geostationary satellite. If the minimum time delay between the dispatch and its getting received , is $y \times 10^{- 2}$ sec, then y is
(Height of geostationary satellite = 36,000 km)

Easy

Solution

$M i n i m u m d i s \tan c e = S = 2 h = 2 \times 36000 k m = 72 \times 10^{6} m M i n i m u m t i m e d e l a y = t = \frac{S}{C} = \frac{72 \times 10^{6}}{3 \times 10^{8}} = 24 \times 10^{- 2} s e c$

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