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Q.

A field of strength 5 × 104/π ampere turns / meter acts at right angles to the coil of 50 turns of area 10-2 m2. The coil is removed from the field in 0.1 second. Then the induced e.m.f in the coil is

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a

0.1 V

b

0.2 V

c

1.96 V

d

0.98 V

answer is A.

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Detailed Solution

B=μ0H=μ0×5×104πe=NBAtime=50×2×10−2×10−20.17=0.11
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