Q.

In fig., the blocks are of equal mass. The pulleyis fixed. In the position shown, A moves with a speed u and the speed of B is v. Then

Moderate

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v=u

v=u/cos⁡θ

v=u/sin⁡θ

v=u sin⁡θ

answer is 2.

(Detailed Solution Below)

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Detailed Solution

See fig.From figurex2+y2=l2∴2xdxdt+2ydydt=2ldldtThere is not vertical motion of the block. Hencedydt=0,dxdt=vx and dldt=vA=uHence 2×vx=2lu or xvx=lu∴vx=lxu=ucos⁡θ.

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