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Questions  

In fig., if process is isothermal then  VC is

a
3 V0
b
2 V0
c
V0
d
none of the above

detailed solution

Correct option is B

Process AB is isochoric. so,PV = n RT∴ P02P0=TATB      or    TB =2TAB C is isothermal process, i.e.,TB=TC=2TAC A represents an isobaric process. HenceV0TA=VCTC  or  VC=TCTAV0=2TATAV0   or VC=2V0

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For one-mole ideal gas, a process follows the relation P=V2V2+V02P0, where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?


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