Questions
Fig.(6) represents an area A = 0.5m2 situated in a
uniform magnetic field B = 2.0weber/m2 and making an angle of 60o with respect to magnetic field. The value of the magnetic flux through the area would be equal to
detailed solution
Correct option is D
Φ=BAcosθ=2⋅0×0⋅5×cos60∘ =2⋅0×0⋅52=0⋅5 weberTalk to our academic expert!
Similar Questions
A small loop of area of cross-section 10-4 m2 is lying concentrically and coplanar inside a bigger loop of radius 0.628 m. A current of 10 A is passed in the bigger loop. The smaller loop is rotated about its diameter with an angular velocity . The magnetic flux linked with the small loop will be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests