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Fig shows the extension ∆l of a wire of length onemetre suspended from the top of a roof at one end and with a load W connected to the other end. If the cross-sectional area of the wire is 10-6m2, the Young s modulus of the material of the wire will be

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a

2×10−11N/m2

b

2×1011N/m2

c

3×10−11N/m2

d

3×1011N/m2

answer is B.

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Detailed Solution

we know that.Y=W⋅lA⋅Δl∴ Y=(40−20)×110−6×(2−1)×10−4=2×1011N/m2.

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