Q.
In Fig., the time taken by the projectile to reach from A to B is t. Then the distance AB is equal to
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a
ut3
b
3ut m2
c
3 ut
d
2ut
answer is A.
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Detailed Solution
Horizontal component of velocity uH=ucos60°=u2 AC=uH×t=ut2 and AB=ACsec30°=ut223=ut3∣
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