Q.

In Fig., the time taken by the projectile to reach from A to B is t. Then the distance AB is equal to

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a

ut3

b

3ut m2

c

3 ut

d

2ut

answer is A.

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Detailed Solution

Horizontal component of velocity uH=ucos60°=u2 AC=uH×t=ut2  and   AB=ACsec30°=ut223=ut3∣
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