In Fig. 16. 57, a wave front AB moving in air is incident on a plane glass surface xy. Its position CD after refraction through a glass slab is shown also along with normals drawn at A and D. The refractive index of glass with respect to air will be equal to :
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a
sin θsin θ'
b
sin θsin ϕ'
c
(BD/AC)
d
(AB/CD)
answer is C.
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Detailed Solution
From shown diagram in questionACvmedium=BDvair ⇒vairvmedium=μ=BDAC