A fighter plane enters inside the enemy territory at time t = 0, with velocity v0 = 250 m/s and moves horizontally with constant acceleration a = 20 m/s2 as shown in fig. (3).An enemy tank at the border, spot the plane and fires shots at an angle θ = 60o with the horizontal and with velocity u = 600 m/s. At what altitude H of the plane it can be hitted by the shot?
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a
15003m
b
125 m
c
1400 m
d
2473 m
answer is D.
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Detailed Solution
Let the fighter plane be hit at point Q.Suppose its horizontal distance is d as shown in fig. Now, d=v0t+12at2=(ucosθ)t∴ t=ucosθ−v0(a/2)=600×(1/2)−250(20/2)=5sFurther, H=(usinθ)t−12gt2=(600×3/2)×5−12×10×25=15003−125=2473m