In figure, AB is a non-conducting rod. Equal charges of magnitude q are fixed at various points on the rod as shown. The rod is rotated uniformly about an axis passing through O and perpendicular to its length such that linear speed of the end A or B of the rod is 3 mis. Magnetic field at O is
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a
11μ0q12π
b
3μ0q7π
c
μ0q2π
d
6μ0q13π
answer is A.
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Detailed Solution
Since the rod is a rigid body, every point has same angular velocity ω=1 rad/s.For points at a distance of 1 m, v1 = 1 m/sFor points at a distance of 2 m, v2 = 2 m/s and for points at a distance of 3m , v3=3msIf a charge rotating in a circle constitutes a current I,B= μ0i2r, where i qt = qv2πrSince field due to rotation of all charges are in same directionB= ∑μ0qv4πr2=μ0q4π 1+1+12 +12 +13 +13⇒B= 11μ0q12π