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Q.

In figure, ABC is the cross section of a right-angled prism and ACDE is the cross section of a glass slab. The value of θ so that light incident normally on the face AB does not cross the face AC is (given sin-1(3/5) = 37°)

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a

θ≤37°

b

θ<37°

c

θ≤53°

d

θ<53°

answer is B.

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Detailed Solution

A = 90° - θc ⇒r2=A=90°-θ>θc cos θ>sin θc=6/52/3=45∵32sinθC=65sin90 (θc is critical angle) θ < cos-145=37°
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