Questions
In figure, ABC is the cross section of a right-angled prism and ACDE is the cross section of a glass slab. The value of so that light incident normally on the face AB does not cross the face AC is (given sin-1(3/5) = 37°)
detailed solution
Correct option is B
A = 90° - θc ⇒r2=A=90°-θ>θc cos θ>sin θc=6/52/3=45∵32sinθC=65sin90 (θc is critical angle) θ < cos-145=37°Talk to our academic expert!
Similar Questions
Light is incident normally on face AB of a prism as shown. A liquid of refractive index is placed on face AC of the prism. The prism is made of glass of refractive index 3/2. The limit of for which total internal reflection takes place on face AC is
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