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Q.

In figure, ABCD is a fixed smooth conducting frame in horizontal plane. T is a bulb of power 100 W, P is a smooth pulley and OQ is a conducting rod. Neglect the self inductance of the loop and resistance of any part other than the bulb. The mass M is moving down with constant velocity 10 m s-1. Bulb lights at its rated power due to induced emf in the loop due to earth's magnetic field. Find the mass M (in kg) of the block. (g = 10 ms-2)

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Detailed Solution

The rate of electrical energy consumed in the bulb = rate of loss of gravitational PE of the mass = Mgv = 100 W. HenceM=10010×10=1 kg
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In figure, ABCD is a fixed smooth conducting frame in horizontal plane. T is a bulb of power 100 W, P is a smooth pulley and OQ is a conducting rod. Neglect the self inductance of the loop and resistance of any part other than the bulb. The mass M is moving down with constant velocity 10 m s-1. Bulb lights at its rated power due to induced emf in the loop due to earth's magnetic field. Find the mass M (in kg) of the block. (g = 10 ms-2)