Q.
In figure, the battery has a potential difference of 20 V. The charge in the capacitor marked as C is
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a
20 μC
b
40 μC
c
10 μC
d
none of these
answer is A.
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Detailed Solution
The circuit can be simplified as follows:Hence Ceq = 2 μF. Thus, charge supplied by battery is Q = 2×20 = 40 μCThis charge will equally divided into two capacitors. Hence, Charge on required capacitor is 20 μC.
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