First slide

Redistribution of charges and concept of common potential

Question

In figure, the battery has a potential difference of 20 V. The charge in the capacitor marked as C is

Moderate

A

$20 μC$
B

$40 μC$
C

$10 μC$
D

none of these

Solution

The circuit can be simplified as follows:
Hence $C_{eq} = 2 μF$ . Thus, charge supplied by battery is $Q = 2 \times 20 = 40 μC$
This charge will equally divided into two capacitors. Hence, Charge on required capacitor is $20 μC$ .

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