Q.

In figure, the battery has a potential difference of 20 V. The charge in the capacitor marked as C is

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a

20 μC

b

40 μC

c

10 μC

d

none of these

answer is A.

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Detailed Solution

The circuit can be simplified as follows:Hence Ceq = 2 μF. Thus, charge supplied by battery is Q = 2×20 = 40 μCThis charge will equally divided into two capacitors. Hence, Charge on required capacitor is 20 μC.
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