Figure below shows a man standing stationary with respect to a horizontal conveyor belt that is accelerating with $$1ms$$–$$2$$. If the coefficient of static friction between the man’s shoes and the belt is $$0.2$$, upto what acceleration of the belt can the man continue to be stationary relative to the belt? (Mass$$ of the man $$=$$ $$65$$ $$kg).

Question

Infinity Learn · Accepted Answer

As the man is standing stationary w.r.t. the horizontal conveyor belt, he is also accelerating at $$1ms$$–$$2$$, the acceleration of the belt. Thus, Acceleration of the man, a $$=1ms$$–$$2$$ Mass of the man,M $$=$$ $$65$$ kgTherefore, net force on the man,ma $$=$$ $$65$$ $$x1=$$ $$65$$ NThe limiting friction between the shoes of the man and the belt is given $$byF=$$μ$$Mg=0.2$$×$$65$$×$$9.8NIf$$, the man can remain stationary upto an acceleration say ‘a’, thenMa′$$=For$$ a′$$=FM=0.2$$×$$65$$×$$9.865=1.96ms$$–$$2$$

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